Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(f2(f2(a, x), y), z) -> f2(f2(x, z), f2(y, z))
f2(f2(b, x), y) -> x
f2(c, y) -> y
Q is empty.
↳ QTRS
↳ Non-Overlap Check
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(f2(f2(a, x), y), z) -> f2(f2(x, z), f2(y, z))
f2(f2(b, x), y) -> x
f2(c, y) -> y
Q is empty.
The TRS is non-overlapping. Hence, we can switch to innermost.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(f2(f2(a, x), y), z) -> f2(f2(x, z), f2(y, z))
f2(f2(b, x), y) -> x
f2(c, y) -> y
The set Q consists of the following terms:
f2(f2(f2(a, x0), x1), x2)
f2(f2(b, x0), x1)
f2(c, x0)
Q DP problem:
The TRS P consists of the following rules:
F2(f2(f2(a, x), y), z) -> F2(x, z)
F2(f2(f2(a, x), y), z) -> F2(f2(x, z), f2(y, z))
F2(f2(f2(a, x), y), z) -> F2(y, z)
The TRS R consists of the following rules:
f2(f2(f2(a, x), y), z) -> f2(f2(x, z), f2(y, z))
f2(f2(b, x), y) -> x
f2(c, y) -> y
The set Q consists of the following terms:
f2(f2(f2(a, x0), x1), x2)
f2(f2(b, x0), x1)
f2(c, x0)
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F2(f2(f2(a, x), y), z) -> F2(x, z)
F2(f2(f2(a, x), y), z) -> F2(f2(x, z), f2(y, z))
F2(f2(f2(a, x), y), z) -> F2(y, z)
The TRS R consists of the following rules:
f2(f2(f2(a, x), y), z) -> f2(f2(x, z), f2(y, z))
f2(f2(b, x), y) -> x
f2(c, y) -> y
The set Q consists of the following terms:
f2(f2(f2(a, x0), x1), x2)
f2(f2(b, x0), x1)
f2(c, x0)
We have to consider all minimal (P,Q,R)-chains.